4.9t^2=36t

Solution for 4.9t^2=36t equation:

4.9t^2=36t

We move all terms to the left:

4.9t^2-(36t)=0

a = 4.9; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·4.9·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*4.9}=\frac{0}{9.8}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*4.9}=\frac{72}{9.8}
=7+1/2.8823529411765
$